{"id":2544,"date":"2023-02-17T19:24:37","date_gmt":"2023-02-17T18:24:37","guid":{"rendered":"http:\/\/matma.com.pl\/?p=2544"},"modified":"2023-02-19T15:21:07","modified_gmt":"2023-02-19T14:21:07","slug":"zadanie-61-0-1-zbior-podstawa","status":"publish","type":"post","link":"http:\/\/matma.com.pl\/?p=2544","title":{"rendered":"zadanie 61 (0-1) zbi\u00f3r podstawa"},"content":{"rendered":"<p>Obliczmy \u015bredni\u0105 wszystkich os\u00f3b:<\/p>\n<p><img decoding=\"async\" src=\"http:\/\/latex.codecogs.com\/gif.latex?\\frac{4\\cdot&amp;space;24+6\\cdot&amp;space;26}{10}=\\frac{96+156}{10}=\\frac{252}{10}=25,2\" alt=\"\\frac{4\\cdot 24+6\\cdot 26}{10}=\\frac{96+156}{10}=\\frac{252}{10}=25,2\" align=\"absmiddle\" \/><\/p>\n<p>Prawid\u0142owa odpowied\u017a to\u00a0<strong>B.<\/strong><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Obliczmy \u015bredni\u0105 wszystkich os\u00f3b: Prawid\u0142owa odpowied\u017a to\u00a0B.<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[44],"tags":[],"class_list":["post-2544","post","type-post","status-publish","format-standard","hentry","category-matura"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v20.1 - 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