{"id":2553,"date":"2023-02-17T20:14:25","date_gmt":"2023-02-17T19:14:25","guid":{"rendered":"http:\/\/matma.com.pl\/?p=2553"},"modified":"2023-02-19T15:19:26","modified_gmt":"2023-02-19T14:19:26","slug":"zadanie-65-0-1-zbior-podstawa","status":"publish","type":"post","link":"http:\/\/matma.com.pl\/?p=2553","title":{"rendered":"zadanie 65 (0-1) zbi\u00f3r podstawa"},"content":{"rendered":"<p>Mamy zbi\u00f3r liczb <img decoding=\"async\" src=\"http:\/\/latex.codecogs.com\/gif.latex?\\left&amp;space;\\{&amp;space;1,2,3,4,5&amp;space;\\right&amp;space;\\}\" alt=\"\\left \\{ 1,2,3,4,5 \\right \\}\" align=\"absmiddle\" \/>. Losujemy dwie liczb\u0119 ze zwracaniem zatem:<\/p>\n<p><img decoding=\"async\" src=\"http:\/\/latex.codecogs.com\/gif.latex?\\left&amp;space;|&amp;space;\\Omega&amp;space;\\right&amp;space;|=5^2=25\" alt=\"\\left | \\Omega \\right |=5^2=25\" align=\"absmiddle\" \/><\/p>\n<p><img decoding=\"async\" src=\"http:\/\/latex.codecogs.com\/gif.latex?A-\" alt=\"A-\" align=\"absmiddle\" \/> zdarzenie polegaj\u0105ce na tym, \u017ce suma wylosowanych liczb b\u0119dzie parzysta<\/p>\n<p><img decoding=\"async\" src=\"http:\/\/latex.codecogs.com\/gif.latex?A=\\left&amp;space;\\{\\left&amp;space;(&amp;space;1,1&amp;space;\\right&amp;space;),&amp;space;\\left&amp;space;(1,3&amp;space;\\right&amp;space;),\\left&amp;space;(&amp;space;1,5&amp;space;\\right&amp;space;),\\left&amp;space;(&amp;space;2,2&amp;space;\\right&amp;space;),\\left&amp;space;(&amp;space;2,4&amp;space;\\right&amp;space;),\\left&amp;space;(&amp;space;3,1&amp;space;\\right&amp;space;),\\left&amp;space;(&amp;space;3,3&amp;space;\\right&amp;space;),\\left&amp;space;(&amp;space;3,5&amp;space;\\right&amp;space;),\\left&amp;space;(&amp;space;4,2&amp;space;\\right&amp;space;),\\left&amp;space;(&amp;space;4,4&amp;space;\\right&amp;space;),\\left&amp;space;(&amp;space;5,1&amp;space;\\right&amp;space;)&amp;space;,\\left&amp;space;(&amp;space;5,3&amp;space;\\right&amp;space;),\\left&amp;space;(&amp;space;5,5&amp;space;\\right&amp;space;)\\right&amp;space;\\}\" alt=\"A=\\left \\{\\left ( 1,1 \\right ), \\left (1,3 \\right ),\\left ( 1,5 \\right ),\\left ( 2,2 \\right ),\\left ( 2,4 \\right ),\\left ( 3,1 \\right ),\\left ( 3,3 \\right ),\\left ( 3,5 \\right ),\\left ( 4,2 \\right ),\\left ( 4,4 \\right ),\\left ( 5,1 \\right ) ,\\left ( 5,3 \\right ),\\left ( 5,5 \\right )\\right \\}\" align=\"absmiddle\" \/><\/p>\n<p><img decoding=\"async\" src=\"http:\/\/latex.codecogs.com\/gif.latex?\\left&amp;space;|&amp;space;A&amp;space;\\right&amp;space;|=13\" alt=\"\\left | A \\right |=13\" align=\"absmiddle\" \/><\/p>\n<p><img decoding=\"async\" src=\"http:\/\/latex.codecogs.com\/gif.latex?P\\left&amp;space;(&amp;space;A&amp;space;\\right&amp;space;)=\\frac{13}{25}\" alt=\"P\\left ( A \\right )=\\frac{13}{25}\" align=\"absmiddle\" \/><\/p>\n<p>Zdanie pierwsze jest<strong> fa\u0142szywe.<\/strong><\/p>\n<p><img decoding=\"async\" src=\"http:\/\/latex.codecogs.com\/gif.latex?B-\" alt=\"B-\" align=\"absmiddle\" \/>zdarzenie polegaj\u0105ce na tym, \u017ce obie liczby b\u0119d\u0105 parzyste<\/p>\n<p><img decoding=\"async\" src=\"http:\/\/latex.codecogs.com\/gif.latex?B=\\left&amp;space;\\{\\left&amp;space;(&amp;space;2,2&amp;space;\\right&amp;space;),\\left&amp;space;(&amp;space;2,4&amp;space;\\right&amp;space;),\\left&amp;space;(&amp;space;4,2&amp;space;\\right&amp;space;),\\left&amp;space;(&amp;space;4,4&amp;space;\\right&amp;space;)\\right&amp;space;\\}\" alt=\"B=\\left \\{\\left ( 2,2 \\right ),\\left ( 2,4 \\right ),\\left ( 4,2 \\right ),\\left ( 4,4 \\right )\\right \\}\" align=\"absmiddle\" \/><\/p>\n<p><img decoding=\"async\" src=\"http:\/\/latex.codecogs.com\/gif.latex?\\left&amp;space;|&amp;space;B&amp;space;\\right&amp;space;|=4\" alt=\"\\left | B \\right |=4\" align=\"absmiddle\" \/><\/p>\n<p><img decoding=\"async\" src=\"http:\/\/latex.codecogs.com\/gif.latex?P\\left&amp;space;(&amp;space;B&amp;space;\\right&amp;space;)=\\frac{4}{25}\" alt=\"P\\left ( B \\right )=\\frac{4}{25}\" align=\"absmiddle\" \/><\/p>\n<p>Zdanie drugie jest\u00a0<strong>fa\u0142szywe.<\/strong><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Mamy zbi\u00f3r liczb . Losujemy dwie liczb\u0119 ze zwracaniem zatem: zdarzenie polegaj\u0105ce na tym, \u017ce suma wylosowanych liczb b\u0119dzie parzysta Zdanie pierwsze jest fa\u0142szywe. zdarzenie polegaj\u0105ce na tym, \u017ce obie liczby b\u0119d\u0105 parzyste Zdanie drugie jest\u00a0fa\u0142szywe.<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[44],"tags":[],"class_list":["post-2553","post","type-post","status-publish","format-standard","hentry","category-matura"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v20.1 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>zadanie 65 (0-1) zbi\u00f3r podstawa - Matma.com.pl<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"http:\/\/matma.com.pl\/?p=2553\" \/>\n<meta property=\"og:locale\" content=\"pl_PL\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"zadanie 65 (0-1) zbi\u00f3r podstawa - Matma.com.pl\" \/>\n<meta property=\"og:description\" content=\"Mamy zbi\u00f3r liczb . 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