{"id":2725,"date":"2023-02-27T15:51:03","date_gmt":"2023-02-27T14:51:03","guid":{"rendered":"http:\/\/matma.com.pl\/?p=2725"},"modified":"2023-04-18T17:30:12","modified_gmt":"2023-04-18T15:30:12","slug":"zadanie-26-0-3-zbior-rozszerzenie","status":"publish","type":"post","link":"http:\/\/matma.com.pl\/?p=2725","title":{"rendered":"zadanie 26 (0-3) zbi\u00f3r rozszerzenie"},"content":{"rendered":"<p>Zr\u00f3bmy rysunek pomocniczy wiedz\u0105c, \u017ce <img decoding=\"async\" src=\"http:\/\/latex.codecogs.com\/gif.latex?\\left&amp;space;|&amp;space;AC&amp;space;\\right&amp;space;|=\\left&amp;space;|&amp;space;BC&amp;space;\\right&amp;space;|\" alt=\"\\left | AC \\right |=\\left | BC \\right |\" align=\"absmiddle\" \/> oraz odleg\u0142o\u015b\u0107 od \u015brodka okr\u0119gu do podstawy tr\u00f3jk\u0105ta <img decoding=\"async\" src=\"http:\/\/latex.codecogs.com\/gif.latex?AB\" alt=\"AB\" align=\"absmiddle\" \/> jest r\u00f3wna <img decoding=\"async\" src=\"http:\/\/latex.codecogs.com\/gif.latex?x\" alt=\"x\" align=\"absmiddle\" \/>.<\/p>\n<p>Niech odcinek <img decoding=\"async\" src=\"http:\/\/latex.codecogs.com\/gif.latex?\\left&amp;space;|AB&amp;space;\\right&amp;space;|=a\" alt=\"\\left |AB \\right |=a\" align=\"absmiddle\" \/>.<\/p>\n<table style=\"border-collapse: collapse; width: 100%;\">\n<tbody>\n<tr>\n<td style=\"width: 50%;\"><img fetchpriority=\"high\" decoding=\"async\" class=\" wp-image-2727 aligncenter\" src=\"http:\/\/matma.com.pl\/wp-content\/uploads\/2023\/02\/Zrzut-ekranu-2023-02-27-151743-268x300.jpg\" alt=\"\" width=\"314\" height=\"352\" srcset=\"http:\/\/matma.com.pl\/wp-content\/uploads\/2023\/02\/Zrzut-ekranu-2023-02-27-151743-268x300.jpg 268w, http:\/\/matma.com.pl\/wp-content\/uploads\/2023\/02\/Zrzut-ekranu-2023-02-27-151743.jpg 403w\" sizes=\"(max-width: 314px) 100vw, 314px\" \/><\/td>\n<td style=\"width: 50%;\"><img decoding=\"async\" src=\"http:\/\/latex.codecogs.com\/gif.latex?P_{\\bigtriangleup&amp;space;ABC&amp;space;}=\\frac{1}{2}a&amp;space;h\" alt=\"P_{\\bigtriangleup ABC }=\\frac{1}{2}a h\" align=\"absmiddle\" \/><\/p>\n<p><img decoding=\"async\" src=\"http:\/\/latex.codecogs.com\/gif.latex?h=R+x\" alt=\"h=R+x\" align=\"absmiddle\" \/><\/p>\n<p>D\u0142ugo\u015b\u0107 <img decoding=\"async\" src=\"http:\/\/latex.codecogs.com\/gif.latex?a\" alt=\"a\" align=\"absmiddle\" \/>\u00a0mo\u017cemy obliczy\u0107 korzystaj\u0105c z twierdzenia Pitagorasa:<\/p>\n<p><img decoding=\"async\" src=\"http:\/\/latex.codecogs.com\/gif.latex?x^2+\\left&amp;space;(&amp;space;\\frac{1}{2}&amp;space;a&amp;space;\\right&amp;space;)^2=R^2\" alt=\"x^2+\\left ( \\frac{1}{2} a \\right )^2=R^2\" align=\"absmiddle\" \/><\/p>\n<p><img decoding=\"async\" src=\"http:\/\/latex.codecogs.com\/gif.latex?\\frac{1}{4}a^2=R^2-x^2\\;&amp;space;\\;&amp;space;\/\\cdot&amp;space;4\" alt=\"\\frac{1}{4}a^2=R^2-x^2\\; \\; \/\\cdot 4\" align=\"absmiddle\" \/><\/p>\n<p><img decoding=\"async\" src=\"http:\/\/latex.codecogs.com\/gif.latex?a^2=4\\left&amp;space;(&amp;space;R^2-x^2&amp;space;\\right&amp;space;)\" alt=\"a^2=4\\left ( R^2-x^2 \\right )\" align=\"absmiddle\" \/><\/p>\n<p>Wiemy \u017ce d\u0142ugo\u015b\u0107 boku nie mo\u017ce by\u0107 liczb\u0105 ujemn\u0105 zatem<\/p>\n<p><img decoding=\"async\" src=\"http:\/\/latex.codecogs.com\/gif.latex?a=2\\sqrt{R^2-x^2}\" alt=\"a=2\\sqrt{R^2-x^2}\" align=\"absmiddle\" \/><\/p>\n<p>Podstawiaj\u0105c powy\u017csze do wzoru na pole mamy:<\/p>\n<p><img decoding=\"async\" src=\"http:\/\/latex.codecogs.com\/gif.latex?P(x)=\\frac{1}{2}\\cdot&amp;space;2\\sqrt{R^2-x^2}\\cdot&amp;space;\\left&amp;space;(&amp;space;R+x&amp;space;\\right&amp;space;)\" alt=\"P(x)=\\frac{1}{2}\\cdot 2\\sqrt{R^2-x^2}\\cdot \\left ( R+x \\right )\" align=\"absmiddle\" \/><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p><img decoding=\"async\" src=\"http:\/\/latex.codecogs.com\/gif.latex?P(x)=\\left&amp;space;(&amp;space;R+x&amp;space;\\right&amp;space;)\\cdot&amp;space;\\sqrt{R^2-x^2}\" alt=\"P(x)=\\left ( R+x \\right )\\cdot \\sqrt{R^2-x^2}\" align=\"absmiddle\" \/><\/p>\n<p style=\"text-align: right;\">Co nale\u017ca\u0142o pokaza\u0107.<\/p>\n<p>Okre\u015blmy dziedzin\u0119 naszej funkcji <img decoding=\"async\" src=\"http:\/\/latex.codecogs.com\/gif.latex?P(x)\" alt=\"P(x)\" align=\"absmiddle\" \/><\/p>\n<p>Promie\u0144 <img decoding=\"async\" src=\"http:\/\/latex.codecogs.com\/gif.latex?R\" alt=\"R\" align=\"absmiddle\" \/> oraz odleg\u0142o\u015b\u0107 \u015brodka okr\u0119gu <img decoding=\"async\" src=\"http:\/\/latex.codecogs.com\/gif.latex?x\" alt=\"x\" align=\"absmiddle\" \/> od do podstawy tr\u00f3jk\u0105ta <img decoding=\"async\" src=\"http:\/\/latex.codecogs.com\/gif.latex?AB\" alt=\"AB\" align=\"absmiddle\" \/> nie mog\u0105 by\u0107 liczbami ujemnymi.<\/p>\n<p>Zatem: <img decoding=\"async\" src=\"http:\/\/latex.codecogs.com\/gif.latex?x&gt;&amp;space;0\\;&amp;space;\\;&amp;space;\\wedge\\;&amp;space;\\;R&gt;&amp;space;0\\;&amp;space;\\;&amp;space;\\wedge&amp;space;\\;&amp;space;\\;&amp;space;R^2-x^2&gt;&amp;space;0\" alt=\"x&gt; 0\\; \\; \\wedge\\; \\;R&gt; 0\\; \\; \\wedge \\; \\; R^2-x^2&gt; 0\" align=\"absmiddle\" \/><\/p>\n<table style=\"border-collapse: collapse; width: 100%;\">\n<tbody>\n<tr>\n<td style=\"width: 50%;\"><img decoding=\"async\" src=\"http:\/\/latex.codecogs.com\/gif.latex?R^2-x^2&gt;&amp;space;0\\;&amp;space;\\;&amp;space;\\Rightarrow&amp;space;\\;&amp;space;\\;&amp;space;\\left&amp;space;(&amp;space;R-x&amp;space;\\right&amp;space;)\\left&amp;space;(&amp;space;R+x&amp;space;\\right&amp;space;)&gt;&amp;space;0\" alt=\"R^2-x^2&gt; 0\\; \\; \\Rightarrow \\; \\; \\left ( R-x \\right )\\left ( R+x \\right )&gt; 0\" align=\"absmiddle\" \/><\/p>\n<p>Uwzgl\u0119dniaj\u0105c powy\u017csze mo\u017cemy zapisa\u0107:<\/p>\n<p><img decoding=\"async\" src=\"http:\/\/latex.codecogs.com\/gif.latex?R^2-x^2&gt;&amp;space;0\\;&amp;space;\\;&amp;space;\\Rightarrow&amp;space;\\;&amp;space;\\;&amp;space;x\\in&amp;space;\\left&amp;space;(&amp;space;0,R\\right&amp;space;)\" alt=\"R^2-x^2&gt; 0\\; \\; \\Rightarrow \\; \\; x\\in \\left ( 0,R\\right )\" align=\"absmiddle\" \/><\/td>\n<td style=\"width: 50%;\"><img decoding=\"async\" class=\"wp-image-2729 aligncenter\" src=\"http:\/\/matma.com.pl\/wp-content\/uploads\/2023\/02\/Zrzut-ekranu-2023-02-27-154413-300x127.jpg\" alt=\"\" width=\"418\" height=\"177\" srcset=\"http:\/\/matma.com.pl\/wp-content\/uploads\/2023\/02\/Zrzut-ekranu-2023-02-27-154413-300x127.jpg 300w, http:\/\/matma.com.pl\/wp-content\/uploads\/2023\/02\/Zrzut-ekranu-2023-02-27-154413.jpg 622w\" sizes=\"(max-width: 418px) 100vw, 418px\" \/><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p><img decoding=\"async\" src=\"http:\/\/latex.codecogs.com\/gif.latex?P(x)=\\left&amp;space;(&amp;space;R+x&amp;space;\\right&amp;space;)\\cdot&amp;space;\\sqrt{R^2-x^2}\" alt=\"P(x)=\\left ( R+x \\right )\\cdot \\sqrt{R^2-x^2}\" align=\"absmiddle\" \/><\/p>\n<p><img decoding=\"async\" src=\"http:\/\/latex.codecogs.com\/gif.latex?D:&amp;space;x\\in&amp;space;\\left&amp;space;(&amp;space;0,R&amp;space;\\right&amp;space;)\" alt=\"D: x\\in \\left ( 0,R \\right )\" align=\"absmiddle\" \/><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Zr\u00f3bmy rysunek pomocniczy wiedz\u0105c, \u017ce oraz odleg\u0142o\u015b\u0107 od \u015brodka okr\u0119gu do podstawy tr\u00f3jk\u0105ta jest r\u00f3wna . Niech odcinek . D\u0142ugo\u015b\u0107 \u00a0mo\u017cemy obliczy\u0107 korzystaj\u0105c z twierdzenia Pitagorasa: Wiemy \u017ce d\u0142ugo\u015b\u0107 boku nie mo\u017ce by\u0107 liczb\u0105 ujemn\u0105 zatem Podstawiaj\u0105c powy\u017csze do wzoru na pole mamy: Co nale\u017ca\u0142o pokaza\u0107. Okre\u015blmy dziedzin\u0119 naszej funkcji Promie\u0144 oraz odleg\u0142o\u015b\u0107 \u015brodka okr\u0119gu [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-2725","post","type-post","status-publish","format-standard","hentry","category-najnowsze-pliki"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v20.1 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>zadanie 26 (0-3) zbi\u00f3r rozszerzenie - Matma.com.pl<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/matma.com.pl\/?p=2725\" \/>\n<meta property=\"og:locale\" content=\"pl_PL\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"zadanie 26 (0-3) zbi\u00f3r rozszerzenie - Matma.com.pl\" \/>\n<meta property=\"og:description\" content=\"Zr\u00f3bmy rysunek pomocniczy wiedz\u0105c, \u017ce oraz odleg\u0142o\u015b\u0107 od \u015brodka okr\u0119gu do podstawy tr\u00f3jk\u0105ta jest r\u00f3wna . Niech odcinek . D\u0142ugo\u015b\u0107 \u00a0mo\u017cemy obliczy\u0107 korzystaj\u0105c z twierdzenia Pitagorasa: Wiemy \u017ce d\u0142ugo\u015b\u0107 boku nie mo\u017ce by\u0107 liczb\u0105 ujemn\u0105 zatem Podstawiaj\u0105c powy\u017csze do wzoru na pole mamy: Co nale\u017ca\u0142o pokaza\u0107. Okre\u015blmy dziedzin\u0119 naszej funkcji Promie\u0144 oraz odleg\u0142o\u015b\u0107 \u015brodka okr\u0119gu [&hellip;]\" \/>\n<meta property=\"og:url\" content=\"https:\/\/matma.com.pl\/?p=2725\" \/>\n<meta property=\"og:site_name\" content=\"Matma.com.pl\" \/>\n<meta property=\"article:published_time\" content=\"2023-02-27T14:51:03+00:00\" \/>\n<meta property=\"article:modified_time\" content=\"2023-04-18T15:30:12+00:00\" \/>\n<meta property=\"og:image\" content=\"http:\/\/latex.codecogs.com\/gif.latex?left&amp;space;|&amp;space;AC&amp;space;right&amp;space;|=left&amp;space;|&amp;space;BC&amp;space;right&amp;space;|\" \/>\n<meta name=\"author\" content=\"lucynabartczak99\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Napisane przez\" \/>\n\t<meta name=\"twitter:data1\" content=\"lucynabartczak99\" \/>\n\t<meta name=\"twitter:label2\" content=\"Szacowany czas czytania\" \/>\n\t<meta name=\"twitter:data2\" content=\"6 minut\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"Article\",\"@id\":\"https:\/\/matma.com.pl\/?p=2725#article\",\"isPartOf\":{\"@id\":\"https:\/\/matma.com.pl\/?p=2725\"},\"author\":{\"name\":\"lucynabartczak99\",\"@id\":\"https:\/\/matma.com.pl\/#\/schema\/person\/b54229c3e035dea49ef8c166c5c63f1e\"},\"headline\":\"zadanie 26 (0-3) zbi\u00f3r rozszerzenie\",\"datePublished\":\"2023-02-27T14:51:03+00:00\",\"dateModified\":\"2023-04-18T15:30:12+00:00\",\"mainEntityOfPage\":{\"@id\":\"https:\/\/matma.com.pl\/?p=2725\"},\"wordCount\":97,\"commentCount\":0,\"publisher\":{\"@id\":\"https:\/\/matma.com.pl\/#organization\"},\"articleSection\":[\"najnowsze pliki\"],\"inLanguage\":\"pl-PL\",\"potentialAction\":[{\"@type\":\"CommentAction\",\"name\":\"Comment\",\"target\":[\"https:\/\/matma.com.pl\/?p=2725#respond\"]}]},{\"@type\":\"WebPage\",\"@id\":\"https:\/\/matma.com.pl\/?p=2725\",\"url\":\"https:\/\/matma.com.pl\/?p=2725\",\"name\":\"zadanie 26 (0-3) zbi\u00f3r rozszerzenie - Matma.com.pl\",\"isPartOf\":{\"@id\":\"https:\/\/matma.com.pl\/#website\"},\"datePublished\":\"2023-02-27T14:51:03+00:00\",\"dateModified\":\"2023-04-18T15:30:12+00:00\",\"breadcrumb\":{\"@id\":\"https:\/\/matma.com.pl\/?p=2725#breadcrumb\"},\"inLanguage\":\"pl-PL\",\"potentialAction\":[{\"@type\":\"ReadAction\",\"target\":[\"https:\/\/matma.com.pl\/?p=2725\"]}]},{\"@type\":\"BreadcrumbList\",\"@id\":\"https:\/\/matma.com.pl\/?p=2725#breadcrumb\",\"itemListElement\":[{\"@type\":\"ListItem\",\"position\":1,\"name\":\"Home\",\"item\":\"https:\/\/matma.com.pl\/\"},{\"@type\":\"ListItem\",\"position\":2,\"name\":\"zadanie 26 (0-3) zbi\u00f3r rozszerzenie\"}]},{\"@type\":\"WebSite\",\"@id\":\"https:\/\/matma.com.pl\/#website\",\"url\":\"https:\/\/matma.com.pl\/\",\"name\":\"Matma.com.pl\",\"description\":\"\",\"publisher\":{\"@id\":\"https:\/\/matma.com.pl\/#organization\"},\"potentialAction\":[{\"@type\":\"SearchAction\",\"target\":{\"@type\":\"EntryPoint\",\"urlTemplate\":\"https:\/\/matma.com.pl\/?s={search_term_string}\"},\"query-input\":\"required name=search_term_string\"}],\"inLanguage\":\"pl-PL\"},{\"@type\":\"Organization\",\"@id\":\"https:\/\/matma.com.pl\/#organization\",\"name\":\"Matma.com.pl\",\"url\":\"https:\/\/matma.com.pl\/\",\"logo\":{\"@type\":\"ImageObject\",\"inLanguage\":\"pl-PL\",\"@id\":\"https:\/\/matma.com.pl\/#\/schema\/logo\/image\/\",\"url\":\"http:\/\/matma.com.pl\/wp-content\/uploads\/2020\/07\/cropped-trudne-1.jpg\",\"contentUrl\":\"http:\/\/matma.com.pl\/wp-content\/uploads\/2020\/07\/cropped-trudne-1.jpg\",\"width\":150,\"height\":30,\"caption\":\"Matma.com.pl\"},\"image\":{\"@id\":\"https:\/\/matma.com.pl\/#\/schema\/logo\/image\/\"}},{\"@type\":\"Person\",\"@id\":\"https:\/\/matma.com.pl\/#\/schema\/person\/b54229c3e035dea49ef8c166c5c63f1e\",\"name\":\"lucynabartczak99\",\"image\":{\"@type\":\"ImageObject\",\"inLanguage\":\"pl-PL\",\"@id\":\"https:\/\/matma.com.pl\/#\/schema\/person\/image\/\",\"url\":\"https:\/\/secure.gravatar.com\/avatar\/a77fc36c9912d50deeefdd4c81a75615386fbe2bdaccb30be7a599c7e140e577?s=96&d=mm&r=g\",\"contentUrl\":\"https:\/\/secure.gravatar.com\/avatar\/a77fc36c9912d50deeefdd4c81a75615386fbe2bdaccb30be7a599c7e140e577?s=96&d=mm&r=g\",\"caption\":\"lucynabartczak99\"},\"url\":\"http:\/\/matma.com.pl\/?author=1\"}]}<\/script>\n<!-- \/ Yoast SEO plugin. -->","yoast_head_json":{"title":"zadanie 26 (0-3) zbi\u00f3r rozszerzenie - Matma.com.pl","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/matma.com.pl\/?p=2725","og_locale":"pl_PL","og_type":"article","og_title":"zadanie 26 (0-3) zbi\u00f3r rozszerzenie - Matma.com.pl","og_description":"Zr\u00f3bmy rysunek pomocniczy wiedz\u0105c, \u017ce oraz odleg\u0142o\u015b\u0107 od \u015brodka okr\u0119gu do podstawy tr\u00f3jk\u0105ta jest r\u00f3wna . Niech odcinek . D\u0142ugo\u015b\u0107 \u00a0mo\u017cemy obliczy\u0107 korzystaj\u0105c z twierdzenia Pitagorasa: Wiemy \u017ce d\u0142ugo\u015b\u0107 boku nie mo\u017ce by\u0107 liczb\u0105 ujemn\u0105 zatem Podstawiaj\u0105c powy\u017csze do wzoru na pole mamy: Co nale\u017ca\u0142o pokaza\u0107. Okre\u015blmy dziedzin\u0119 naszej funkcji Promie\u0144 oraz odleg\u0142o\u015b\u0107 \u015brodka okr\u0119gu [&hellip;]","og_url":"https:\/\/matma.com.pl\/?p=2725","og_site_name":"Matma.com.pl","article_published_time":"2023-02-27T14:51:03+00:00","article_modified_time":"2023-04-18T15:30:12+00:00","og_image":[{"url":"http:\/\/latex.codecogs.com\/gif.latex?\\left&amp;space;|&amp;space;AC&amp;space;\\right&amp;space;|=\\left&amp;space;|&amp;space;BC&amp;space;\\right&amp;space;|"}],"author":"lucynabartczak99","twitter_card":"summary_large_image","twitter_misc":{"Napisane przez":"lucynabartczak99","Szacowany czas czytania":"6 minut"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"Article","@id":"https:\/\/matma.com.pl\/?p=2725#article","isPartOf":{"@id":"https:\/\/matma.com.pl\/?p=2725"},"author":{"name":"lucynabartczak99","@id":"https:\/\/matma.com.pl\/#\/schema\/person\/b54229c3e035dea49ef8c166c5c63f1e"},"headline":"zadanie 26 (0-3) zbi\u00f3r rozszerzenie","datePublished":"2023-02-27T14:51:03+00:00","dateModified":"2023-04-18T15:30:12+00:00","mainEntityOfPage":{"@id":"https:\/\/matma.com.pl\/?p=2725"},"wordCount":97,"commentCount":0,"publisher":{"@id":"https:\/\/matma.com.pl\/#organization"},"articleSection":["najnowsze pliki"],"inLanguage":"pl-PL","potentialAction":[{"@type":"CommentAction","name":"Comment","target":["https:\/\/matma.com.pl\/?p=2725#respond"]}]},{"@type":"WebPage","@id":"https:\/\/matma.com.pl\/?p=2725","url":"https:\/\/matma.com.pl\/?p=2725","name":"zadanie 26 (0-3) zbi\u00f3r rozszerzenie - Matma.com.pl","isPartOf":{"@id":"https:\/\/matma.com.pl\/#website"},"datePublished":"2023-02-27T14:51:03+00:00","dateModified":"2023-04-18T15:30:12+00:00","breadcrumb":{"@id":"https:\/\/matma.com.pl\/?p=2725#breadcrumb"},"inLanguage":"pl-PL","potentialAction":[{"@type":"ReadAction","target":["https:\/\/matma.com.pl\/?p=2725"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/matma.com.pl\/?p=2725#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/matma.com.pl\/"},{"@type":"ListItem","position":2,"name":"zadanie 26 (0-3) zbi\u00f3r rozszerzenie"}]},{"@type":"WebSite","@id":"https:\/\/matma.com.pl\/#website","url":"https:\/\/matma.com.pl\/","name":"Matma.com.pl","description":"","publisher":{"@id":"https:\/\/matma.com.pl\/#organization"},"potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/matma.com.pl\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"pl-PL"},{"@type":"Organization","@id":"https:\/\/matma.com.pl\/#organization","name":"Matma.com.pl","url":"https:\/\/matma.com.pl\/","logo":{"@type":"ImageObject","inLanguage":"pl-PL","@id":"https:\/\/matma.com.pl\/#\/schema\/logo\/image\/","url":"http:\/\/matma.com.pl\/wp-content\/uploads\/2020\/07\/cropped-trudne-1.jpg","contentUrl":"http:\/\/matma.com.pl\/wp-content\/uploads\/2020\/07\/cropped-trudne-1.jpg","width":150,"height":30,"caption":"Matma.com.pl"},"image":{"@id":"https:\/\/matma.com.pl\/#\/schema\/logo\/image\/"}},{"@type":"Person","@id":"https:\/\/matma.com.pl\/#\/schema\/person\/b54229c3e035dea49ef8c166c5c63f1e","name":"lucynabartczak99","image":{"@type":"ImageObject","inLanguage":"pl-PL","@id":"https:\/\/matma.com.pl\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/a77fc36c9912d50deeefdd4c81a75615386fbe2bdaccb30be7a599c7e140e577?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/a77fc36c9912d50deeefdd4c81a75615386fbe2bdaccb30be7a599c7e140e577?s=96&d=mm&r=g","caption":"lucynabartczak99"},"url":"http:\/\/matma.com.pl\/?author=1"}]}},"_links":{"self":[{"href":"http:\/\/matma.com.pl\/index.php?rest_route=\/wp\/v2\/posts\/2725","targetHints":{"allow":["GET"]}}],"collection":[{"href":"http:\/\/matma.com.pl\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"http:\/\/matma.com.pl\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"http:\/\/matma.com.pl\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"http:\/\/matma.com.pl\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=2725"}],"version-history":[{"count":2,"href":"http:\/\/matma.com.pl\/index.php?rest_route=\/wp\/v2\/posts\/2725\/revisions"}],"predecessor-version":[{"id":2731,"href":"http:\/\/matma.com.pl\/index.php?rest_route=\/wp\/v2\/posts\/2725\/revisions\/2731"}],"wp:attachment":[{"href":"http:\/\/matma.com.pl\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=2725"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"http:\/\/matma.com.pl\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=2725"},{"taxonomy":"post_tag","embeddable":true,"href":"http:\/\/matma.com.pl\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=2725"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}